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(a) Find the equilibrium solutions of the following dierential equations. You should find three y*= y^3-6y^2+ 11y-6 (b) Draw the phase line diagram
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ok so \[y' = y ^{3} -6y^{2} +11y - 6\] factoring the right side you get (y-1)(y-2)(y-3) = 0 so for the solutions it is y =1, y=2 y=3
Nicely done Robots!
Thank you but how exactly did you factor it? that's my main issue.
You could try using the rational roots theorem, then using polynomial long division. It's not pretty, but it would work.
thank you! i'll look that up : )
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