Question

x^3y^3-y=x ... by implicit differentiation find dy/dx

Answer 1

use product rule
d(dx) (u*v) = udv+vdu
x^3*3y^2 *dy/dx + y^3*3x^2 - dy/dx = 1
x^3*3y^2 *dy/dx - dy/dx = 1 - y^3*3x^2
(x^3*3y^2 - 1) * dy/dx = 1 - y^3*3x^2
(1 - y^3*3x^2) / (x^3*3y^2 -1) = dy/dx

Answer 2

thank you so much!!!!!!!!!

Answer 3

you're welcome. make sure to check the work and understand the problem.

Answer 4

yes, that's what im doing now