Question

-1/n + (m/n)^2?

Answer 1

What exactly are you required to do for this problem?

Answer 2

Im sorry only the m ^2. Solve by adding.

Answer 3

What class are you taking?

Answer 4

I believe the answer is -1+m / n^3. The m wasnt ^2 it was the n. sorry im confusing. Prealgebra

Answer 5

OH okay...

Answer 6

-n+m^2 /n^2

Answer 7

I'm confused how you got that jamie. I'm gonna write the problem out again. It is -1/n + m/n^2

Answer 8

I have a prgram that does the problem for me if i type it in but let me check

Answer 9

yeah thats what i got.

Answer 10

Wow then I totally do not know what im doing. dang it

Answer 11

hahah download the program its really nice.
its called algerbrator i think its 30$

Answer 12

I will look into that

Answer 13

lol

Answer 14

Thanks

Answer 15

if you're still confused, multiply -1/n by n/n (=1)
then you'll have common denominators (n^2)

Answer 16

INT jamie said her answer is right and mine is wrong so i have been sitting here confused trying to figure it out

Answer 17

yeah, jamie is correct
(-1/n)*(n/n)=(-n)/(n^2)
[(-n)/(n^2)]+[(m^2)/(n^2)]=(m^2-n)/(n^2)

Answer 18

you can do this because n/n is just 1

Answer 19

Thanks so much