Question

Differentiate:
g(x) = tan^3(sec(x^3))

Answer 1

Derivate by starting with the inner derivative and work outwards.

Answer 2

yes but the outer derrivitive will be sec (inside derrivative) right instead of tan

Answer 3

Is it:

d(x^3) * d(sec(u)) * d(tan(v))

(3x) (sec(x^3)tan(x^3)) (sec^2(sec(x^3))) ???

Answer 4

....3x^2...yada yada yada....

Answer 5

use chain rule...it is
3(x)^2tan^2(sec(3x).sec^2sec(x^3).sec(x^3)tan(x^3)

Answer 6

there is some mistake in upper solution this is right one 3(x^2)^3tan^2(sec(x^3).sec^2sec(x^3).sec(x^3)tan(x^3)