Question

solve the integral: (y-1)/e^y dy

Answer 1

Ok so I'm about to use integration by parts.
int(udv) = uv - int(vdu)
u = y-1
du = 1 dy
dv = e^-y
v = -e^-y
This gives: uv - int(vdu) = (y-1)(-e^-y) - int(-e^-y)dy
= (y-1)(-e^-y) + int(e^-y)dy (I pulled out a negative from the integral)
= (y-1)(-e^-y) - e^-y + C
= -y*e^-y + e^-y - e^-y + C
= -y*e^-y + C

Answer 2

THANK YOU!.....i have more if you want to enjoy them!

Answer 3

You're welcome. Make sure to check the work.
Eh... I had to do ~250 integrals last month, so I'm not sure that I would want to do all of them. It's really important that you do them yourself, but if you find a few that you absolutely can't get after several tries, feel free to ask for help.

Answer 4

i will be asking, thank u very much