Physics Question!: Can you help me find the velocities in the x and y direction when a ball is thrown a distance of 9.14 meters and the amount of time it took to land in another person's hand is 1.37 seconds. Use kinematics please.
vel. at which time. tell me the way of throwing. is it horizontally or vertically or parabolic.
initial velocities, and parabolic.
here the horizontal distance(R) it travel is =initial horizontal vel.(Ux) * total time taken(T) R =Ux*T Ux=R/T=9.14/1.37 =6.67 m/s now the total vertical displacement is zero as it start from the ground & end with it. vertical displacement(H) =Uy*T-1/2(a*T^2) (Uy=initial vertical vel. ,a=vert. acc. = g=9.8) H=Uy*T -1/2( g*T^2) 0 =Uy*1.37 -0.5*9.8*1.37*1.37 Uy =9.19/1.37= 6.713 m/s so Ux=6.67 m/s Uy= 6.713 m/s
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