Question

differentiate G(t)=t^3cost

Answer 1

I am assuming that G(t) = (t^3)(cos(t)); use product rule to derive.

Dx(f(x)) = L'R + LR'

Dx(G(x)) = (3t^2)(cos(t)) + (t^3)(-sin(t))
G'(x) = (3t^2)(cos(t)) - (t^3)(sin(t))
G'(x) = (t^2) [3cos(t) - t sin(t)]

thats the best I can do with it :)

Answer 2

just for correction its:

G'(t) = .....

Answer 3

ok thanks

Answer 4

can u answer any chemistry questions

Answer 5

?

Answer 6

I dont know much about chemistry, sorry...

Answer 7

np