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using the chain rule for derivative... (1+4x)^5(3+x-X2)^8.. I don't need the answer, only the way to do it. 1st step 2nd
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ummm hold on
brb ill try and get sum1 2 help u
ok thx
First apply product rule to (1+4x)^5 and (3+x-x^2)^8
Chain rule is applied when finding the derivatives of those two polynomials. What you do is take the derivative of the thing overall (the (1+4x)^5 derives to 5*(1+4x)^4) and multiply it by the inside of it ( the 1+4x derives to 4) So the derivative of (1+4x)^5 is 5*4*(1+4x)^4.
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Using what I showed you for that one, can you figure out how to derive (3+x-x^2)^8?
yes thank u so much
Glad I could help. =] gl
WHat is the probablity when 4 coins are tossed, and three are heads-binomial problem
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