Question

what are the critical points of 30(x-2)^2(x-4)^3

Answer 1

Differentiate that!
30 * (2(x-2)*(x-4)^3 + 3(x-4)^2(x-2))
Set equal to zero...
30 * (2(x-2)*(x-4)^3 + 3(x-4)^2(x-2)) = 0
2(x-2)*(x-4)^3 + 3(x-4)^2(x-2)) = 0
x = 4 and x = 2

Answer 2

I'd love a "become a fan" button clicked :D

Answer 3

sorry i meant the critical points of f'(x) = 30(x-2)^2(x-4)^3

Answer 4

So of that function...?
Then you gotta' differentiate it anyways and you'd get the same thing.