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Find the derivative h(x) = ln(cosh(6x))
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h'(x) = (1/cosh(6x) ) * 6 h'(x) = 6 / cosh(6x)
so you dont do chain rule?
it said that answer is wrong
I might have it wrong, actually... I thought h was a variable again... 1 / cosh(6x) * sinh(6x) * 6
ok i saw my mistake, i forgot to put last 6
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thank u
:D Glad to help. Teaching me something too.
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