Question

2sin^2 theta + 3cos theta -3 =0

tyler, answer meee!! LOL

Answer 1

\[\sin^2 \theta = 1 - \cos^2 \theta\]

Answer 2

\[2(1-\cos^2 \theta)- 3 \cos \theta -3 = 0\]

Answer 3

\[2-2\cos^2 \theta - 3 \cos \theta -3 = 0\]

Answer 4

\[-2 \cos^2 \theta - 3\cos \theta-1 = 0\]

Answer 5

times everything by -1
\[2\cos^2\theta + 3\cos \theta +1 = 0\]

Answer 6

factor
\[(2 \cos \theta + 1 )( \cos \theta + 1 ) = 0\]

Answer 7

solve the two parts...
(2cosθ+1) = 0 or (cosθ+1)=0
cos θ =- .5 or cos θ = -1

Answer 8

θ = 120, 240, 180

Answer 9

-fin-

Answer 10

hmm...

Answer 11

is that the pythagorean id?

Answer 12

\[\sin^2\theta=1−\cos^2\theta\] is Pythagorean's Identity

Answer 13

you meant -1 not equals 1.. right?

Answer 14

if you flip it around, \[1 = \sin^2\theta + \cos ^2\theta\]

Answer 15

ooh.