Question

∫[2^(X^(2))x,]dx=

Answer 1

Try letting u=x^2

Answer 2

du=2xdx then.

Answer 3

or you can say du/2=xdx

Answer 4

If y=a^x, lny=ln(a^x)=xlna => y'/y=lna => y'=y(lna)=(a^x)lna
Integrate both sides to get y=int((a^x)lna,x)=lna(int(a^x,x)) => y/lna=int(a^x,x) => (Remember y=a^x) a^x/lna=int(a^x,x) (Don't forget about your constant C) => int(a^x,x)=a^x/lna + C. So if you have 1/2*int(2^u,u)=1/2*(2^u/ln2)+C (Almost done! Put back in terms of x)

Answer 5

Hey that does say int(2^(x^(2)), x)? right?