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Mathematics 12 Online
OpenStudy (anonymous):

hello I am trying to understand why the limit of as x->0 from the right for (lnx)/(sinx) is -infinity

OpenStudy (anonymous):

use l'hosptitals rule

OpenStudy (anonymous):

I am I just dont undesrtand how you get that answer

OpenStudy (anonymous):

the top gives me 1/x and the bottom cos x which is still undetermined at the top

OpenStudy (anonymous):

that equals 1/xcosx

OpenStudy (anonymous):

i get that part but how does that end up being negative infinity

OpenStudy (amistre64):

as ln(x) approaches 0 we go to negative infinity as sin(x) approaches 0 we go to 1

OpenStudy (amistre64):

the graph of ln(x) as it approaches 0 drops down and down and down and never touches 0....it goes to -inf.

OpenStudy (anonymous):

got it thank you

OpenStudy (amistre64):

yay!! :)

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