Question

A 20 ft diagonal brace on a bridge connects a support of the center of the bridge to a side support on the bridge.The horizontal distance that it spans is 4 ft longer than that the height reaches on the side of the bridge.Find the horizontal and vertical distances spanned by this brace.

Answer 1

dude, I just figured out im am idiot :)

9 * 7 = 63 and 9 =2+7....

Answer 2

what is this

Answer 3

the last question you had; the area = 63; and length is w+2.....

Answer 4

I missed it when I did (w+2)(w)... it equals w^2 + 2w....

NOT: w^2 + w my mistake

Answer 5

you mean to tell me we did alllllllllll that for nothing...........it did seem a little complicated.....lol

Answer 6

lol.....good practice I guess :)

Answer 7

so our final answer is...........

Answer 8

Lenght = 9 and width =7 is what we were supposed to get, and that i the correct answer.

Answer 9

so this question here is a triangle: and we use the formula h^2 + b^2 = d^2 or whatever letter you wanna use.

we know that the span is 4ft longer than its height

Answer 10

lets set it up:

h^2 + (h+4)^2 = 20^2

h^2 + h^2 +8h +16 = 400

Answer 11

2h^2 +8h +16 -400 =0

2h^2 +8h -384 = 0

2(h^2 +4h -192) = 0...I hope im right so far :)

Answer 12

2(0) = 0 so...


h^2 +4h -192 = 0

h= -4/2 + sqrt(16 - (4)(1)(192))/2

Answer 13

h= -2 + sqrt(784)/2

Answer 14

h = 14 - 2 = 12

h=12 and span =16.

Answer 15

when I double check, it works like a dream :)

Answer 16

looks about right to me

Answer 17

i had to get my brains back :)

Answer 18

you been doing too much math.........lol

Answer 19

lol.... i do agree

Answer 20

I wanna be like you when I grow up..........lol!