Question

Find the slope of the line tangent to the curve at x.

y = -7x2 + 5x; x = 11

Answer 1

When you see slope think derivative? The derivation is the slope at every point of the curve. y'=? Then evaluate y' at x=11

Answer 2

derivative*

Answer 3

\[y = -7x ^{2} + 5x\]
\[x = 11\]
Take the derivative, so
\[y' =-14x + 5 \]
Then plug in 11,
and the slope at x = 11 is -14(11) + 5 = -149

Answer 4

thank you!! i saw an example like that on the internet but i didnt think it would be that easy, thank you so much

Answer 5

Very welcome!

Answer 6

i just posted another question, if u could at least explain to me how it works...