Question

cscx-cotxcosx=sinx im a little lost.

Answer 1

identities... get everything in terms of "sin" and "cos" is usually a good strategy.

Answer 2

1/sin - (cos/sin)(cos) = sin

Answer 3

1 - cos^2
-------- = sin
sin

Answer 4

remember that:

sin^2 + cos^2 = 1
and

sin^2 = 1 - cos^2

Answer 5

sin^2
----- = sin
sin

sin=sin

Answer 6

I had got so far as 1/sinx - cosx/sinx(cosx)

Answer 7

you were doing good :) what stumped ya?

Answer 8

I didnt know what to do after that. Im using a program called ALEKS to do my homework and its less than helpful.

Answer 9

lol .... I always did homework with a pencil and paper. Back in my day that was considered prime property :)

Answer 10

well im using the paper too. okay 1-sinx - cosx/sinx then what?
I already have a common denominator, so I subtract cosx from 1?

Answer 11

let me write it out:

sin - sin^2 - cos
-------------- ??? is this what you have
sin

Answer 12

what is the original equation?

Answer 13

cscx-cotxcosx=sinx

Answer 14

1 - cos cos 1 - cos^2
-- --- --- = -- -----
sin sin 1 sin sin

Answer 15

1 - cos^2 sin^2 sin
-------- = ----- = ---
sin sin 1

Answer 16

gotcha. I didnt think to put the cosx over one. it makes more sense now. thank you

Answer 17

happy to oblige :)

Answer 18

okay new question