How do I do square root y^3 * cubed square root y^2? I am totally confused with this problem.

Question

How do I do square root y^3 * cubed square root y^2?  I am totally confused with this problem.

anonymous · Answer

is this $$y^{3}\sqrt[3]{y^2}$$  you are working with?

anonymous · Answer

under a square root sign?

anonymous · Answer

If I'm reading you right, then your equation would look like y^(3/2)*y^(2/3). With same bases, you would add your exponents, so 3/2+2/3=13/6. Your answer is y^13/6, which you can simplify.

anonymous · Answer

Remember that roots are just the base raised to 1 over whatever you are rooting to. For example, the square root of y is the same as y^(1/2), and the cube root is y^(1/3). Prove this to yourself on a calculator with y as any number. If your base already has an exponent, that exponent becomes the numerator. So square root of y^3 is y^(3/2) and cube root of y^2 is y^(2/3).

yrivers36 · Answer

Mfang its not an equation.  Its radicals.

yrivers36 · Answer

Daomowon its $$\sqrt{y ^{3}}$$

yrivers36 · Answer

thats not what i typed...omg going crazy over this problem

yrivers36 · Answer

its that prob X sqrt y^3

yrivers36 · Answer

there is a sqrt sign with the y^3

yrivers36 · Answer

mfang Im sorry your correct

anonymous · Answer

no need to worry, whatever I just typed didn't come up but $$y^3 = y^2*y$$, then