Question

what does -1/2(tan(x) limit -pi/3to pi/3 equal to

Answer 1

i am having trouble understanding your statement. Can you state the problem as a sentence?

Answer 2

the problem is 1/2 (tan x) the limit is -pi/3 to pi/3 (you have to plug these values into x) i didn't get the right answer, i want to c what the problem is

Answer 3

is this calculus?

Answer 4

yes

Answer 5

\[\lim_{x\rightarrow -\frac{\pi}{3}}\frac{1}{2}\tan x\]

Answer 6

is that the question?

Answer 7

no i found the integral of the problem which came out to be (1/2tanx) the limit is -pi/3 to pi/3. could u plug it in and tell me what u get

Answer 8

okay

Answer 9

you should state your question more clearly

Answer 10

\[\frac{\sqrt{3}}{2}\]

Answer 11

how did u get a positive number

Answer 12

was the definite integral \[\int^{\frac{\pi}{3}}_{-\frac{\pi}{3}}\frac{1}{2} \sec^2 x dx\]

Answer 13

at any rate \[\frac{1}{2}\left\{\tan(\frac{\pi}{3})-\tan(-\frac{\pi}{3})\right\}\]

Answer 14

\[=\frac{1}{2}\left\{\frac{\sqrt{3}}{2}-(-\frac{\sqrt{3}}{2})\right\}\]

Answer 15

\[=\frac{1}{2}\frac{\sqrt{3}}{4}\]

Answer 16

sorry that was wrong

Answer 17

latex error

Answer 18

\[\frac{1}{2} 2\sqrt{3}\]

Answer 19

did it again

Answer 20

so -pi/3= sqrt3/2

Answer 21

no

Answer 22

i mean tan of that angle

Answer 23

but \[\tan(-\frac{\pi}{3})=-\frac{\sqrt{3}}{2}\]

Answer 24

got ya, but no

Answer 25

man

Answer 26

tangent is negative in the fourth quadrant

Answer 27

look at the tangent graph or the unit circle to comfirm

Answer 28

k ty