Question

dy/dx=(y-1)^2 cos(piex)
Find the particular solution y=f(x) wo the differential equation with the initial condition f(1)=0.

Answer 1

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Answer 2

Oh hi, there's your question!
dy = (y-1)^2 cos(pi * x) dx
dy / (y-1)^2 = cos(pi *x) dx
-(y-1)^-1 = sin(pi * x) +C
Plug in x = 1 and y = 0 to find C
-(-1)^-1 = sin(pi) + C
1 = 0 + c
C = 1

Answer 3

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Answer 4

hi! thanks. how do i know when to solve for c? and i will. your awesome!