(xlny+xy) if i differentiate that with respect to y... i think i get 0
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OpenStudy (anonymous):
When you differentiate with respect to y, all you do is treat the \(x\) variable as a constant. Since \(\ln{y}\) doesn't differentiate to zero, and neither does \(y\), you shouldn't get zero.
OpenStudy (anonymous):
ok wat do i get
OpenStudy (anonymous):
cn you show me
OpenStudy (anonymous):
how to do it den
OpenStudy (anonymous):
So the derivative of \(\ln{y}\) is \(\frac{1}{y}\), and the derivative of \(y\) is \(1\). Does that help get you moving?
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myininaya (myininaya):
He didn't say partial derivative
OpenStudy (anonymous):
i got the answer x/y+x
myininaya (myininaya):
This could be implicit differiention
OpenStudy (anonymous):
is that rite
OpenStudy (anonymous):
Yep, that's right. Unless myininaya is right about it being implicit differentiation. Are you learning about implicit differentiation now, or partial derivatives?
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myininaya (myininaya):
If we aren't doing partial differentiation, the answer is x'lny+x/y+x'y+x