solve sq. y-13 + sq.y =13
First get 1 sqrt thingy by itself then square both sides so you can get rid of that sqrt but you will still have another sqrt on the other side so you get that one by itself and then square again
no more sqrt thingy
so we have (y-13)^(1/2)=13-y^1/2
square both sides
y-13=(13-y^(1/2))^2
sorry to interrupt. @myinaya, like the way you said "sqrt thingy" XD
lol
i just thought it is easier to understand
y-13=169-2y^1/2+y
remember get that last sqrt thingy by itself
y-y-13-169=2y^(1/2)
oh mine thought we ran into some like terms. Lets just combine them real quick
though*
-199=2y^(1/2)
so we have -199/2=y^(1/2) then square both sides (-199/2)^2=y
You should always check your solutions when you raise both sides to an even power though
so y= -199/2^2
y = (-199/2)^2
and actually it was suppose to be (199/2)^2 but it doesnt matter since it is squared
this is so confusing to me ....haven't been in school for 20+ years
like i forgot to write a negative sign before the last step
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