Question

(sinx/1+cosx)+(1+cosx/sinx)=2cscx

Answer 1

try to combine the fractions

Answer 2

I was doing that. but It keeps telling me its wrong

Answer 3

which one should be the common denominator?

Answer 4

the sinx?

Answer 5

is that suppose to be sinx/(1+cosx)+(1+cosx)/sinx

Answer 6

to find a common denominator multiply the first fraction by sinx/sinx and the second fraction by (1+cosx)/(1+cosx)

Answer 7

I think the common denominator would be (1+cosx)(sinx)

Answer 8

so now you have [(sin)^2+1+2cosx+(cosx)^2]/[sinx(1+cosx)]=[1+1+2cosx]/[sinx(1+cosx)]=2(1+cosx)/[sinx(1+cosx)]=2/sinx=2cscx

Answer 9

wait, what?

Answer 10

im lost