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(a) integrate the function over the interval (b) find the area of the region between the graph and the x-axis. y=-x^2+5x-4, [1,4]
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(S) -x^2 +5x -4 dx (-1/3)x^3 +(5/2)x^2 -4x | 1,4 [(-1/3)4^3 +(5/2)4^2 -4(4)] -[(-1/3) +(5/2) -4]
-24 + (11/6)
is it -133/6 ?
Yes, that is the answer I got. Thank you so much for all of your help.
So basically -133/6 is the area of the region. Right?
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