Question

Yet another identity problem - (sin^2 B - tan^2 B) / 1 - sec^2 B = sin ^2 B

Answer 1

We know sin^2 = 2 sin cos

Answer 2

1 - sec^2 = tan^2

Answer 3

-(sin^2 - tan^2)
-------------- = sin^2
tan^2

Answer 4

-sin^2 tan^2
----- + ----- = sin^2
tan^2 tan^2

Answer 5

-sin^2
--------- + 1 = sin^2
sin^2
----
cos^2

Answer 6

flip the bottom and multiply to get:

-cos^2 +1 = sin^2

1 - cos^2 = sin^2

sin^2 = sin^2

Answer 7

Oops, the original equation's numerator is (sin^2 - tan^2). I'm so sorry for typing that wrong! Thanks for doing it, it must have been hard.

Answer 8

........... and I got outta bed for this? :)

Answer 9

multiply both sides by (-1) and you get the same result.... I think

Answer 10

Yes, you do, and thank you soooooo much and sorry for the mistake!