Question

how do i graph y=-1 over x + 1 on a graph??

Answer 1

you mean you want to sketch y= -1 on a graph right?

Answer 2

im not sure, thats why im looking for help where ever i can get it. i have an assignment due wednesday and that is one of the questions. the teacher is very little help and hasnt told me what to do. can you help?

Answer 3

what does the question really say?

Answer 4

the question says: on graph D draw y=-1 over x+1

Answer 5

graph D is x + 1 right?

Answer 6

well i know it isnt equal to negative one.

Answer 7

hmmm if so, then you have point y as -1 and you can find x :

y = x + 1
-1 = x + 1
x = -2

so , your point on that graph must be at (-2,-1) I guess.

Answer 8

since you want to graph y= -1 on x + 1, then they are equal at some point

Answer 9

? when you over do you mean it is a fraction like -1/(x+1)

Answer 10

I think that's what he meant! then I have misread the question again lol, sorry

Answer 11

yes

Answer 12

then @matto forget my answer, I have misread the question, dearest apology

Answer 13

Do you know what 1/x looks like?

Answer 14

hyperbola

Answer 15

to graph such question you have to find the limits to find the HAs and VAs

Answer 16

just move the graph over 1 in the positive direction

Answer 17

yes, it is bacically a an open c shape that only takes up one quater of a quadratic graph. im not sure how t explain it

Answer 18

sorry over 1 in the negative direction

Answer 19

he can't do that without finding the HAs and VAs

Answer 20

you have to find the limit :

\[\lim_{x \rightarrow \pm \infty} y \] to find the HAs

and

\[\lim_{x \rightarrow -1\pm}\] to find the VAs

Answer 21

to see where the function's position will be in the end

Answer 22

that's it :)

Answer 23

im sorry, but in all seriousness, i have absolutly no idea what that means.

Answer 24

lol, alright

did you take limits?

Answer 25

thank you!
actually I have been strugling with this problem too... thanks now i am starting to get it...
btw, I think you could be a GREAT lecturer

Answer 26

thanks andy ^_^ I'm flattered

Answer 27

maths is easily my weakest subject, im doing 4 3A/B subjects for year 12 and i was hoping this migh help.

Answer 28

don't worry, it will help. I was weak in mathematics , but then I got on my feet and worked hard and look where have I reached :)

Answer 29

@ matto, did you take limits?

Answer 30

what is a limit?

Answer 31

this :\[\lim_{a \rightarrow b} f(x) \] = L

do you recognize this?

Answer 32

im sorry, no. as i have said, my teacher has done very little teaching over the last 8 weeks.

Answer 33

oh, btw, I have a book called "calculus" =D
its like 1000 pages, anyone want it?
If it feels too big, I also have Calculus Essentials, maybe you want this?

Answer 34

andy, can you explain the problem for him please? :) brb

Answer 35

the problem looks simple, but also looks uncomplete... I cant really get what the question means..

Answer 36

it also asks to include all asymptotes if tha helps. i dont know what an asymptote is.

Answer 37

In analytic geometry, an asymptote of a curve is a line such that the distance between the curve and the line approaches zero as they tend to infinity.

Answer 38

http://upload.wikimedia.org/wikipedia/commons/d/d3/1-over-x-plus-x_abs.svg


like this

Answer 39

ok, well, its ok if you cant help. i appreciate the help. this was basically a last resort for me, i will seek help else where.

Answer 40

you know, i think you should go to your friends
ask them to help
if they dont,
go to your teacher
if she doesnt,
go to library

Answer 41

if library doesnt, drop it, go do something fun...

Answer 42

back, alright @matto

Answer 43

i will ask my friends

Answer 44

An asymptote is a line you draw on the graph that limits the graph from extending , contracting etc

we have 2 types of asymptotes

1) Horizontal asymptotes are the lines that cut the y-axis horizontaly, you find them by taking the limit of f(x) as x goes to infinity like this:

\[\lim_{x \rightarrow \pm \infty} f(x)\]

and you take the limit from the left and right, if you end up with the limit = :


if you end up with an answer that is a number, then that number is you Horizontal asymptote.

2) Vertical asymptotes are the lines that cut the x-axis, and you find them by taking the limit of x, as x goes to a number that makes your denominator 0, in your function which is y = -1/x+1 , x=-1 your number :

\[\lim_{x \rightarrow 1\pm} f(x)\]

\[\infty , -\infty\]

then x = 1 is your Vertical Asymptote

Answer 45

I hope he got the meaning and difference between HAs and VAs

Answer 46

i hope so too

Answer 47

it's not simple to explain it without showing him the graph by hand

Answer 48

x = -1 * instead of x=1 sorry ^^"