Question

find the derivative of:

y= ln[(3x-1)^3 (4x+2)^5)

Answer 1

y = ln(u^3 v^5) u = 3x-1 ; v=4x+2

or

y = ln(uv) ; u = (3x-1)^3 v=(4x+2)^5

Answer 2

eiher way uv is on the bottom ans the top works out to be u'v' right?

Answer 3

so i have to use the power rule?

Answer 4

for the top yes; Dx(uv)

Answer 5

thank yos so much. i just get confused when choosing which rule to use. =D

Answer 6

uv' + u'v

the top is:

[(3x-1)^3] [20(4x+2)^4] + [9(3x-1)^2][(4x+2)^5]

might wanna clean that up some tho...

Answer 7

im going to work it out using the formula n then im going to check it up with your answer.

thank you so much ^.^