How do I change the order of integration for the following equation...(i'll use the equation editor below)

Question

anonymous · Answer

$$I=\int\limits_{0}^{\pi/2}\int\limits_{x}^{\pi/2} [(\sin y) / (y)]  dy dx$$

anonymous · Answer

my solution is the following:
if we draw the area of the integral, we can see it's bounded by the lines:
$$x=y, x=0, y=\pi/2$$
so x changes from $$x=0 \to x=y$$, and we can fix y as $$y=0 \to y=\pi/2$$
the integral I will be as:
$$I=\int\limits_{0}^{\pi/2}\int\limits_{0}^{y}(siny/y)dxdy$$
which will result in a value $$I=1$$