Determine the critical numbers of the given function and classify each critical point as a relative maximum, relative min or neither.
f(t)= t/(t^2+3)
I can get to t/(t^2+3)
I need to solve for 0 to find the intervals of increase and decrease. I have forgotten how to solve for 0 with this problem.

Question

anonymous · Answer

You got nowhere.

anonymous · Answer

I know i need the 1st derivitive. Which I got 
t(2t) - (t^2+3)(1) / (t^2+3)^2
Is that much correct?

amistre64 · Answer

f'(x) = [ BT' - B'T ] / B^2

amistre64 · Answer

(t^2 +3)(1) - (t)(2t)
----------------
      (t^2 +3)^2

amistre64 · Answer

any second opinions?  :)

nowhereman · Answer

I agree, but _please_ use the equation-editor: $$f'(t) = \frac{t^2 + 3 - 2t\cdot t}{(t^2+3)^2}$$

amistre64 · Answer

t^2 +3 -2t^2 = 0

-t^2 +3 = 0

-t^2 = -3

t^2 = 3

t=+-sqrt(3)

anonymous · Answer

I have that. I just have the top reversed.

nowhereman · Answer

and you were missing parentheses

amistre64 · Answer

I cant get that equation editor to work right .....

nowhereman · Answer

you can simply enclose the latex-code in \ [ and \ ].

amistre64 · Answer

latex is for painting houses ;)

anonymous · Answer

amistre64 is right:
$$f'(x)= \frac{3-t^2}{(t^2+3)^2}$$

amistre64 · Answer

something likethis?  testing $$45\Omega -\sin(45) -\infty$$

amistre64 · Answer

I do better after a nap :)

nowhereman · Answer

sleep well :-)