how do you find the 5th derivative of tan(x) using tan^2(x)+1 as the first derivative instead of sec^2(x) ?

Question

anonymous · Answer

i already have the second and 4rd derivatives but i'm getting really confused on the 4th

amistre64 · Answer

....concentration :) .....

myininaya · Answer

I'm to the fourth derivative now and it's all way to the end of the page. lol

anonymous · Answer

same here

anonymous · Answer

so much algebra, what's your fourth derivative?

myininaya · Answer

attachment

myininaya · Answer

i don't wanna simplify

myininaya · Answer

This problem is gross

anonymous · Answer

i agree my professor is horrible ):

myininaya · Answer

did you see my attachment?

anonymous · Answer

i'm trying to open it, i haven't gotten there yet.

myininaya · Answer

88*(1+tan(x)^2)^2*tan(x)^2+16*(1+tan(x)^2)^3+16*tan(x)^4*(1+tan(x)^2) is what my friendly computer algebra system got for the 5th derivative

anonymous · Answer

hah noice

anonymous · Answer

yeah thats pretty much where i'm at with it ):

anonymous · Answer

yeah my fifth derivative  involves too much product rule.

anonymous · Answer

i'm working it with someone on chat, and we're keeping everything in terms of tan, its working much easier that way.

myininaya · Answer

( think you everything you get a (secx)^2, you are suppose to write it as 1+(tanx)^2

myininaya · Answer

maybe there is a pattern we havent noticed

anonymous · Answer

yea i checked my derivatives with your derivatives and it checks but it gets drawn out.