14-10c=94
\[ \begin{align*} (14-10c) - 14 &= 94 - 14\\ -10c &= 80\\ \frac{-10c}{-10} &= \frac{80}{-10}\\ c &= -8 \end{align*} \]
how did you put -14 next to 14-10c
I was just showing that I was subtracting 14 from both sides.
from which
94 and which one
And \(14-10c\).
??????
may you please show me step by step im very confused
So when you have an equation (with an equal sign saying one thing is equivalent to another), in order to preserve the equality, you have to do the same thing ot both sides of the equation. For example, if you have \(5=5\), if you add \(2\) to both sides, the equality is still preserved: \[ \begin{align*} 5 &= 5\\ 5 + 2 &= 5+2\\ 7 &= 7 \end{align*} \]
So I did the same thing with your equation, except instead of adding two, I subtracted 14.
The thing with my math teacher she wants us to show it step by step
Yeah, so the first step would be subtracting 14 from both sides.
so
14-10c=94 -14 =-14 --------------- -10c=94
?
Well, what's \(94-14\).
so its
14-10c=94 -14 =-14
Well, what I was saying is that the final equation you wrote shouldn't have been \(-10c = 94\), it should be \(-10c = 80\), as \(94-14 = 80\).
oh okay :-) Thankyou !
Glad I could help!
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