Find the probability that a point X, selected randomly on line LQ, is on the given segment. 1)Line LM 2)line NP 3)line OQ 4)line MQ
its upside down sorry about that
The probability would be the ratio of the segment lengths to the total. Let \[S_{AB} = The\ length\ of\ a\ segment\ from\ A\ to\ B\] \[P_{AB} = The\ probability\ for\ a\ random\ point\ to\ be\ on\ the\ segment\ AB\] \[ \rightarrow P_{LM} = S_{LM}/S_{LQ}\] \[ \rightarrow P_{NP} = S_{NP}/S_{LQ}\] \[ \rightarrow P_{OQ} = S_{OQ}/S_{LQ}\] \[ \rightarrow P_{MQ} = S_{MQ}/S_{LQ}\] etc.
The probability of x being on a line segment is the length of the segment divided by the total length of the line. Which part of this is confusing?
so the first one would be 2/17
Nearly. 2 is the length of LM, but the length of LQ is not 17.
so 2/24
Yes.
Np=12/24 OQ= 12/24 MQ= 19/24
MQ is 22 units in length. Otherwise those numbers are correct.
okay thank you
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