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Mathematics 12 Online
OpenStudy (anonymous):

Find the probability that a point X, selected randomly on line LQ, is on the given segment. 1)Line LM 2)line NP 3)line OQ 4)line MQ

OpenStudy (anonymous):

OpenStudy (anonymous):

its upside down sorry about that

OpenStudy (anonymous):

The probability would be the ratio of the segment lengths to the total. Let \[S_{AB} = The\ length\ of\ a\ segment\ from\ A\ to\ B\] \[P_{AB} = The\ probability\ for\ a\ random\ point\ to\ be\ on\ the\ segment\ AB\] \[ \rightarrow P_{LM} = S_{LM}/S_{LQ}\] \[ \rightarrow P_{NP} = S_{NP}/S_{LQ}\] \[ \rightarrow P_{OQ} = S_{OQ}/S_{LQ}\] \[ \rightarrow P_{MQ} = S_{MQ}/S_{LQ}\] etc.

OpenStudy (anonymous):

The probability of x being on a line segment is the length of the segment divided by the total length of the line. Which part of this is confusing?

OpenStudy (anonymous):

so the first one would be 2/17

OpenStudy (anonymous):

Nearly. 2 is the length of LM, but the length of LQ is not 17.

OpenStudy (anonymous):

so 2/24

OpenStudy (anonymous):

Yes.

OpenStudy (anonymous):

Np=12/24 OQ= 12/24 MQ= 19/24

OpenStudy (anonymous):

MQ is 22 units in length. Otherwise those numbers are correct.

OpenStudy (anonymous):

okay thank you

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