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solve the equation. Separate by commas, if more than one answer. x^(2)9^(x)-2x9^(x)=3(9^(x))
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\[x ^{2}9^{x}-2x9^{x}=3(9^{x})\]
Do this...
Bring over the right-hand side and take out the common factor of 9^x. You have\[9^x(x^2-2x-3)=0\]
That means
either \[9^x=0\]or\[x^2-2x-3=0\]
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There is no x here that will make 9^x zero (if you plot any exponential function, you'll see that it never crosses below the x-axis)
Thanks a lot for explaining the steps, much appreciated.
But,\[x^2-2x-3=(x+1)(x-3)\]so your second factor has that\[(x+1)(x-3)=0 \rightarrow x=-1,3\]
No worries.
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I will! :)
how do I become a fan though?
There should be a blue link next to my name...says, "Become a fan"
nice, very nice
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