Find the surface area of a sphere of radius r, using calculus.
omg i know this
give me just a sec
that would be amazing if you could help! :)
so the equation of a circle having center (0,0) is x^2+y^2+r^2
oh surface area not volume one sec. let me rething my strategy
ok. thanks
Use the formula for the surface area of a general equation revolved around the x-axis. If you start with x^2 + y^2 = r^2, and your function is y, then f(x) = sqrt(r^2-x^2). The formula for the surface area of revolution is, in this case, \[SA = 2 \pi* \int\limits_{-r}^{r} \ \ f(x) * \sqrt{1+f(x)^2}\] Integrate and simplify.
Sorry, inside the root of the integrand it should be f'(x)^2.
what is the circumference of sphere
Thanks QuantumModulus, that helped a lot!!
Glad to help. :)
have you done trig substition yet?
I think you may have to do in one of the steps
nvm it is a simple integration
ok but i think was suppose to get 4pi*r^2
let me know what you get?
ok it is 4*pi*r^2 because the semicirlce is being revolved about the x axis
Yes! :)
ignore the extra stuff on that attachment
I have to go. You can check your work with the attachment just ignore the But part. goodnight
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