Question

Find the amplitude, period, and phase shift of the function?

y= 8sin(5/6x-pi/5)

Answer 1

we know that the general formula is the following:\[y = A*\sin(\omega t +\theta)\]

Answer 2

so in this case we can compute the following:

- A = 8
-\[\theta\] (phase shift) = pi/5
- w = 5/6 (t)

Answer 3

I forgot what w = ? to really, but if you have te formula for w, then you can computer t ^_^

Answer 4

the*

Answer 5

compute*

Answer 6

\(\omega = 2\pi f\) where \(f\) is the reciprocal of the period.

Answer 7

thank you abhorsen ^_^

Answer 8

No problem :)

Answer 9

so in this case:\[T= 2\pi / w = 2\pi /5/6 = 7.5\]

Correct me if I'm wrong

Answer 10

T= 7.5 secs

Answer 11

wait I forgot f lol

Answer 12

nvm F ^^"

Answer 13

Final Answer:

- A = 8
- phase angle = pi/5
- T = 7.5 secs