curvilinear motion: parametric equations: y(t)=-4.9t^2 +4.864t+1.2192 and x(t)=5.08t... i found the equations for velocity individually etc etc. Find the formula for the speed of the particle at any time, t?

Question

anonymous · Answer

you need to derive the equations individually, then take $$(dy/dt)/(dx/dt)$$ to find the velocity at any time, you should have t in the equation as f(t) = velocity

anonymous · Answer

so $$(-9.8t+4.864)/5.08$$?

anonymous · Answer

but isint dy/dx just height in terms of distance? not speed in terms of time?

anonymous · Answer

(−9.8t+4.864)/5.08 is correct.... NO dy/dx means the change in y(dependent variable) divided by the change in x (independent variable)

anonymous · Answer

you can apply this concept to the rate of people per room, rate of population per year, and many more.

anonymous · Answer

oh i see! because i am simply dividing the rates of distance while keeping it in terms of time, i keep the integrity of the independent variable

anonymous · Answer

thank you so much

anonymous · Answer

no problem ... keep up the good work... math is all about the notation... if you understand that the logic will become easier.

anonymous · Answer

the next question asks to find dy/dx ... O.o

anonymous · Answer

:D