Question

sinxcosx(dy/dx)+y=sinx how to find y?

Answer 1

you mean y' right?

Answer 2

y' = cosx ^_^

Answer 3

wait a min, it's:

y' + y = sinx

Answer 4

right?

Answer 5

if so, then y= sinx - y'

Answer 6

y'=(sinx-y)/(sinxcosx)
?
i dont fully understand the question DX

Answer 7

lol no, the question is :

y' + y = sinx

Answer 8

whats the sinxcosx?

Answer 9

wait....it's the derivative of sinxcosx + y = sinx

Answer 10

so y = sinx + sin^x + cos^2x
= sinx + 1
= sinx

Answer 11

sin^2x*

Answer 12

there's something wrong ._.

Answer 13

whats wrong?

Answer 14

mowazzem can you please restate the question

Answer 15

in a more understandable way

Answer 16

sinxcosxy'+y=sinx

Answer 17

find y' or y?

Answer 18

its a derivative, i need to solve this

Answer 19

that's mean y

Answer 20

you want to derive y = sinx - sinxcosx?

Answer 21

linear homogeneous

Answer 22

again, mowa is this the question you want to derive:

y = sinx - sinxcosx?

Answer 23

no this is not a question. its a DERIVATIVE FORM sinxcosx(y')+y=sinx

Answer 24

and you want to find y?

Answer 25

yeah

Answer 26

then y = sinx - sinxcosxy'

Answer 27

as far as I have understood from the problem

Answer 28

wait, do you want to integrate?!

Answer 29

right hand side has also a derivative of y'. so your suggestion might be worng

Answer 30

lol! so you DO want to integrate ^_^

Answer 31

what class is this? calculus or diff equas?

Answer 32

I think it's calculus since she wants to get y

Answer 33

diff equas

Answer 34

only way to get rid of y' is to integrate

Answer 35

oh, no wonder, diff euas (at that level) are just beyond me

Answer 36

just a little*

Answer 37

mowa, did you take integration by parts?

Answer 38

sstaica what do you do?

Answer 39

did you take integration?

Answer 40

do you know bernoulli equation

Answer 41

heard of it

Answer 42

y'+p(x)y=r(x)

Answer 43

general form of bernoullis equation

Answer 44

its semelar form of previous equation

Answer 45

hmm, the bernoulli that I know comes from physics P + 1/2pV^2 + pgh

Answer 46

are undergraduate student

Answer 47

you mean a college student?

Answer 48

yeah

Answer 49

yep I am, first year ^_^

Answer 50

or graduate student

Answer 51

why? :)

Answer 52

ok, probably you don't know

Answer 53

are you a graduate?

Answer 54

its higher class math

Answer 55

I am doing PhD

Answer 56

I see, then you are right, I prolly don't know it :) still taking calculus II ^_^

Answer 57

whoa! GOOD LUCK :)

Answer 58

i know that why you usde very simple rule

Answer 59

lol, still learning ^^"

anyways, sorry for not being able to help , I wish I could help though, you can try google? or youtube ^_^

Answer 60

and I wish you the best of luck :)

Answer 61

its very simple but I forgot. I done it about 4 yrs ago.

Answer 62

you can try google though , the only way I know right now is integration by parts

Answer 63

anyaway thanks

Answer 64

np ^_^

Answer 65

haha yup diff equas are some crazy fun stuff XD

Answer 66

mowazzem, can i ask you a question?

Answer 67

sorry i am going out. What you wanna ask?