The speed of sound in the air is proportional to the square root of the
absolute temperature. At 20 °C the speed of sound is 343 m/s. What is the
speed of sound at –10 °C? (0 °C = 273 K).

Question

nowhereman · Answer

Just solve: $$ \frac{x}{\sqrt{273 - 10}} = \frac{343}{\sqrt{273+20}} $$ because that is what proportional means.

anonymous · Answer

how do you get kelvin from celcius?

nowhereman · Answer

It's just a simple translation [K] = [C] + 273.15, but you should see this from my previous answer.

anonymous · Answer

am i not supposed to use something like   $$(spped of sound)  \alpha  temperature ^{2}$$ ?

anonymous · Answer

speed = k * temperature ^ 2

anonymous · Answer

?

nowhereman · Answer

No, you said yourself, that the speed of sound v is proportional to the square root of the temperature T, so $$v \sim \sqrt{T} ⇔ ∃ k: v = k\cdot \sqrt{T}$$

anonymous · Answer

oh, i get it

anonymous · Answer

thanx

anonymous · Answer

so, is the answer 325? because thats what i got

anonymous · Answer

anwar, can you please fan lokisan, because he helped me alot and i can only fan him once

nowhereman · Answer

Yes, 325 is about right. A more exact value I got, using 1 deg C = 273.15 K, is 324.975677595.