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\[(k^2)^4\]
?
simplify
\[k ^{2*4} = k ^{8}\]
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i yhought if there was an exponent outside perentheses. you made (in this case 4) of whats inside them?
yes
so 4 twos are 16
but you can do it my way too, it is simpler
they are bothe totally different answerss. wich is right
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ok, let me show you
for example, lets say k is 2, so \[(2^{2})^{4}\] = \[(2^{2})*(2^{2})*(2^{2})*(2^{2})\] =4*4*4*4 =256
now, to see if my way gives the same answer, lets see:
\[(2^{2})^{4} = 2^{2*4} = 2^{8}\] = 2*2*2*2*2*2*2*2 =256 so both mothods are exactly the same just that mine is easyer
got it? i would apreciate if you fan me (it is just fun =D)
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