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Mathematics 8 Online
OpenStudy (anonymous):

just checking click it.. =)

OpenStudy (anonymous):

\[(k^2)^4\]

OpenStudy (anonymous):

?

OpenStudy (anonymous):

simplify

OpenStudy (anonymous):

\[k ^{2*4} = k ^{8}\]

OpenStudy (anonymous):

now, become my fan =D

OpenStudy (anonymous):

i yhought if there was an exponent outside perentheses. you made (in this case 4) of whats inside them?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

so 4 twos are 16

OpenStudy (anonymous):

but you can do it my way too, it is simpler

OpenStudy (anonymous):

they are bothe totally different answerss. wich is right

OpenStudy (anonymous):

ok, let me show you

OpenStudy (anonymous):

for example, lets say k is 2, so \[(2^{2})^{4}\] = \[(2^{2})*(2^{2})*(2^{2})*(2^{2})\] =4*4*4*4 =256

OpenStudy (anonymous):

now, to see if my way gives the same answer, lets see:

OpenStudy (anonymous):

\[(2^{2})^{4} = 2^{2*4} = 2^{8}\] = 2*2*2*2*2*2*2*2 =256 so both mothods are exactly the same just that mine is easyer

OpenStudy (anonymous):

got it? i would apreciate if you fan me (it is just fun =D)

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