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Mathematics 16 Online
OpenStudy (anonymous):

Does this series converge or diverge? (n*2^n)/(2^n + 3^n) and by which test

OpenStudy (anonymous):

you can simply take values or take the limit as x --> infinity^_^

OpenStudy (anonymous):

the limit as x-->infinite is zero, which is inconclusive

OpenStudy (anonymous):

no no, it means that the series converge ^_^

OpenStudy (anonymous):

when you end up with zero, it means the series is converging :) and when you end up with infinity it diverges

OpenStudy (anonymous):

the series will not necessarily converge when the limit of the sequence as n-->infinite is zero, for example 1/n

OpenStudy (anonymous):

Sorry sstarica, that is not correct

OpenStudy (anonymous):

I need another test

OpenStudy (anonymous):

prifk is right

OpenStudy (anonymous):

i was thinking limit comparison or ratio

OpenStudy (anonymous):

but ratio yields "1", inconclusive.. and not sure what converging or diverging series to limit compare to

OpenStudy (anonymous):

Simplifying a bit will help here..\[(n*2^n)/(2^n + 3^n) = n/[1 + (3/2)^n]\]

OpenStudy (anonymous):

yes, I did that. not sure what the next steps are ... l'hopitals rule says the limit goes to zero

OpenStudy (anonymous):

perhaps a comparison of some sort?

OpenStudy (anonymous):

this question was driving me mad and I'm a tutor lol!

OpenStudy (anonymous):

You tried the ratio test?

OpenStudy (anonymous):

yes. 1

OpenStudy (anonymous):

i'll try again

OpenStudy (anonymous):

yeah, still 1

OpenStudy (anonymous):

converge. Ask hinted by polpak, write (n*2^n)/(2^n + 3^n) as n/[1 + (3/2)^n]. Then compare this with n(2/3)^n which is convergent by the Ratio test

OpenStudy (anonymous):

Nice!

OpenStudy (anonymous):

well done! thank you

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