Question

I have one more question to whomever would love to explain to me how u solve this equation. m=7/8;(5,-7)

Answer 1

y-(-7)=m(x-5) so you just sub in the gradient and solve

Answer 2

i know how to write out the equation but after that im lost =(

Answer 3

What's the question? just to find the equation?

Answer 4

im sorry its for an online course

Answer 5

the question is find the equation of the line having the given slope and containing the given point

Answer 6

You sub it into the point-gradient formula, which is y-y1=m(x-x1)
so using the given, sub in your gradient and your y and x-values to get:

y-(-7)=(7/8)(x-5)
8(y+7)=7(x-5)
7x-8y-35-56=0
7x-8y-91=0

Answer 7

Does that help? :I

Answer 8

im trying to go over it

Answer 9

You need to find the slope of the original line because the new line is parallel to it and therefore must have the same slope. Then you can write the equation for the new line using the point slope formula
\[y-y_0 = m(x-x_0)\]

Where y0 and x0 are the y and x coordinates of a point on the line, and m is the slope of the line.

Answer 10

where do u get 56 from

Answer 11

8(y+7)=7(x-5)
8y+56=7x-35
0=7x-8y-35-56

Answer 12

its not the answer

Answer 13

I just threw everything over to one side..

Answer 14

answer is 7/8x-

Answer 15

83/8

Answer 16

Ohhh you get that answer if you don't get rid of the fraction

Answer 17

and leave 8 as the denominator

Answer 18

right whichs is what i wasnt understandin

Answer 19

When you leave it as a fraction:

y-(-7)=(7/8)(x-5)
y+7=(7x/8) - 35/8)

Answer 20

hold on

Answer 21

can someone type out the working, leaving it in fractional form, it's taking so long for me, ha

Answer 22

y = (7x/8) - (91/7) confirmed

Answer 23

\[y+7=[7/8](x-5) \rightarrow y = (7x)/8 - (7*5)/8 -7 \]
\[\rightarrow y = (7/8)x - 35/8 - 56/8 = (7/8)x - 91/8\]