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Mathematics 19 Online
OpenStudy (laddiusmaximus):

secx+sinx(-tanx)=cosx prove

OpenStudy (anonymous):

1/cos(x) + sinx(-sin/cos) = cosx You have a common denominator so you have (1 - sin^2x)/cosx = cosx 1 - sin^2x = cos^2x by the sin^2x + cos^2x = 1 identity cos^2x/cosx = cosx cosx = cosx

OpenStudy (anonymous):

secx= 1/cosx tanx=sinx/cosx plug them into your equation you have 1/cosx=sinx. (-sinx)/cosx

OpenStudy (anonymous):

SORRY "+" instead of "="

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