Ask your own question, for FREE!
Mathematics 6 Online
OpenStudy (anonymous):

how do you solve e^x = x

OpenStudy (anonymous):

by taking ln for both sides

OpenStudy (anonymous):

Use Newton-raphson method

OpenStudy (anonymous):

what is the newton-raphson method?

OpenStudy (anonymous):

taking the ln does not anything

OpenStudy (anonymous):

please help nowhereman

OpenStudy (nowhereman):

there is no analytic solution, so you should use an approximation method like Newton's tangent method

OpenStudy (anonymous):

how do you know there is no analytic solution?

OpenStudy (anonymous):

you're right. ln does not solve the problem

OpenStudy (nowhereman):

oh wait, there is no solution at all, because \[ e^x >= 1 + x \]

OpenStudy (anonymous):

ya, e^x always larger than x, so e^x = x does not have any solution

OpenStudy (anonymous):

you are wrong. The answer is nonreal, which i am well aware of. I know what the number is to many decimal places. (Just take the ln of any number over and over again), but i have no idea how to find the number.

OpenStudy (anonymous):

you have to iterate using computer methods to find this value

OpenStudy (anonymous):

can you prove that?

OpenStudy (anonymous):

If you use the moivre's theorem you know that e^(ix) = isinx + cosx or something like that

OpenStudy (anonymous):

I used software program and found that x=-W(-1), where W(z) is the product log function

OpenStudy (anonymous):

what software did you use? did u use wolfram alpha? what is the product log function?

OpenStudy (anonymous):

yes.. here is the definition of the function http://www.wolframalpha.com/input/?i=product+log+function

OpenStudy (anonymous):

ok

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!