(x/x-2)-(x/x+2)=1
I think something wrong in the question .... please correct it. Use "Equation" button to get the equation in good shape
do you think there are infinetly many solutions or none at all
Simplify the left hand side will give you (4x)/(x^2 - 4) = 1 [(4x)/(x^2 - 4) ]- 1 = 0 (x^2 - 4x - 4)/(x^2 - 4) = 0 => x^2 -4x -4 = 0 which you can solve by using the quadratic formula
show me how to use it pls
roots are \[-2 (\sqrt(2) -1)and 2 ( \sqrt(2) +1)\]
kynosis is this the answer
Kynosis, you know how to type out the quadratic formula nicely, please show to Tru769150
I don't know how to type it here, sorry Tru
but is what kynosis posted the answer
\[ x=\frac{-b \pm \sqrt {b^2-4ac}}{2a}, \] which a is the coefficient of the x^2 term b is the coefficient of the x^1 term c is the coefficient of the x^0 term
so can you show me how i write this in there x^2-4x-4=0
Find the common denominator which is (x-2)(x+2) then the equation is \[x^2 -4x -4 = 0\]
\[ x=\frac{4 \pm \sqrt {4^2+4(4)}}{2}, \]
simplify and you have the same answer
so it would be 4+or -4squrt of 2/2
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