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m^-2 n^-5 0ver (m^4 n^3)^-1
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do you mean \[(m ^{-2}n ^{-5})/(m ^{4}n ^{3})^{-1}\]
yes
the exponent -1 on the bottom makes everything on the bottom move to the top
then you just combine like terms...
so the m^-2 and the m^4 becomes m^2
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since \[x ^{a}x ^{b}=x ^{a+b}\]
can you try to combine the n's
yeah
but its a negative exponet and you cant have a negative exponet in your final answer
then the negative exponent will move back to the denominator
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so the final answer should be m^2/n^2
ohhhhh
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