Question

Equation Simplification Help Please...

Answer 1

\[(2(k+1)!/4^{k+1})\times(4^{k}/(2k)!)\]

Answer 2

4^k/4^(k+1) simplifies to 1/4, which means that your expression simplifies to (k+1)!/(2(2k)!).

Answer 3

Sorry! Just realised I missed out a pair of brackets!\[((2(k+1))!/4^{k+1})\times(4^{k}/(2k)!)\]

Answer 4

is it: \[(2(k+1))!/4(2k)!\]

Answer 5

\[[2(k+1)]! = [2k+2]*[2k+1]*[2k]!\]

See if that doesn't help simplify.

Answer 6

I think I get (4k^2+5k+2)/4

Answer 7

Close. Should be

\[(2k+1)(k+1)/2 = (2k^2 + 3k + 1)/2\]

Answer 8

How did you get that? Aren't we left with the [2k+2]∗[2k+1] on top

Answer 9

yes, and 4 on bottom. You can divide 2k+2 by 2, leaving (k+1)*(2k+1) on top and 2 on the bottom.

Answer 10

Haha! What's wrong with me today... That was obvious! Thanks for all your help mate. Any chance you could send me your email or something so I can contact you when I don't find you here? You've been a massive help to me today!

Answer 11

http://dpaste.com/526875/

Answer 12

Let me know when you get it. and send me an email.

Answer 13

got it mate.

Answer 14

Send me a quick email and I'll delete the dpaste.

Answer 15

Sent.