Question

Integrate b=0 a=2 x(x-3) dx=??

Answer 1

\[\int\limits_{0}^{2} x(x-3) dx=?\]

Answer 2

Multiply it out and integrate term by term.
\[= \int\limits_{0}^{2} x^2 - 3x\ dx\]

Answer 3

(x^3) -(3x^2)/2 and then use the integration limits

Answer 4

(x^3)/3 -(3x^2)/2 *

Answer 5

i know the answer is -10/3 but i cant seem to get it. Idk what im missing

Answer 6

ok so we have (2^3)/3 = 8/3
and 3(2^2)/2 = 3*4/3 = 4 so
for the limit 2 we get
8/3 - 4 =

and limit 0 will just be 0 for x so it will turn out to be 0.

so final answer is 8/3 -4 = 8/3 - 12/3 = -4/3

Answer 7

woops hold on lol error

Answer 8

the answer is -10/3 according to the book. I think where you have 4, it should be 6 right? that works out i think

Answer 9

it shuld be 8/3 - 6 = 8/3 - 18/6 = -10/3

Answer 10

8/3 - 18/3 = -10/3 *

Answer 11

thank you for the help... im new to the site... anybody want to give me a quick overview?

Answer 12

in general, we post doubts and other people try to help...

Answer 13

i see that... i dont know how i have never heard of this site... it would have been a lifesaver for calculus this semester

Answer 14

hahaha!