Question

sqrt (16x- 16) + sqrt (25x^3- 25x^2)

Answer 1

my teacher told us not to like mess with the binomials so im confused

Answer 2

You can factor coefficients out of the first inside expression, so you get:
sqrt(16(x-1)) - sqrt(25x^2(x-1)).
The 16 in the first term comes to be a 4 on the outside.
The 25x^2 inside the second term comes to be a 5x on the outside.
4sqrt(x-1)-5x*sqrt(x-1)

And you can simplify by factoring out the sqrt(x-1):
sqrt(x-1)*(4-5x).

Answer 3

im so confused

Answer 4

Do you get that (16x-16)=16(x-1)?

Answer 5

o k now i get it wen u put it simplerr

Answer 6

But 16 is a square so you can bring out it's root

Answer 7

but its connected to a binomial
so wich one of them...or both
and 25 is also a square connected to a binomial in the laast half of the problem

Answer 8

Well, we rewrite \(\sqrt{16(x-1)}\) as \(\sqrt{16}\sqrt{x-1}\) and simplify.

Answer 9

Can you rewrite the second half now?

Answer 10

yse so the answer is 5x + 4 sqrt x-1?

Answer 11

(4-5x)

Answer 12

and i knock off the sqrt x-1?

Answer 13

no, no, no, just replace the 5x+4 with (4-5x)

Answer 14

o okay

Answer 15

do u mean 4 + 5x