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4 sqrt 3 +2 sqrt 1/3
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Okay, so first we can break down the different terms. In the second term, we have\[\sqrt{1/3} = \sqrt{1/3} * \sqrt{3}/\sqrt{3} = \sqrt{3}/3,\] correct?
yes and i thought u said u were doing it on a whiteboard. is that wat this is? (:
so i have 4 sqrt 3 + 2 sqrt 3 over regular 3
Nah, the link for the whiteboard site is elsewhere, I can give it to you if you'd like to go there though. :) Then, we can look at the whole: \[4 * \sqrt{3} + 2/3 * \sqrt{3}\] And we can factor out the sqrt(3): \[\sqrt{3}*(4+2/3)\] and you can solve that on your own. :)
so in order to get common denominators the answer will turn out to be 14 sqrt 3/ regular 3 rightt...?
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Yep, you've got it. ;D
thank u so much!!!!!
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