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do you know how to differientate sin(x^y)
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Use the chain rule. d(f(g(x))/dx = g'(x) * f'(g(x)).
you mean :\[(\sin(x))^y\] ?
If that is y = sin(x^y), then you have to use implicit differentiation.
\[(\sin (x)^{y} \times y) \div \tan (x)\]
the derivative will be \[\cos(x ^{y})*(x^y)\prime\]
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to differentiate \[(x^y)\prime\] you implicitly differentiate by setting = z
\[z=(x^y)\prime\]\[\ln(z)=yln(x)\]\[zprime/z=(y/x)*x \prime+\ln(x)*y \prime\]\[z \prime=z*(all that stuff)\]
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