Intergration please solve intergral tanx^3 dx
odd degree trig functions; I think its easier to split them up into groups of something...
Re-write it as ∫tan^2(x)*tan(x) dx ---> ∫(sec^2(x)-1)*tan(x) dx = ∫sec^2(x)tan(x) - tan(x) dx. Let u=tan(x).
well, it is quite simple actually, just wait a minute and sstarica will show you
re-write it and you'll get :\[\int\limits_{}^{}sinx^3/cosx^3 dx\] use u substitution for cosx^3 ^_^ give it a try :)
LOL andy :D
Here, use this :)
oh, and ssarica, gratz on making a Superstar, I guess I cant call you starlet anymore
lol, call me whatever you want and thank you ^_^, some of the fanning came from you :)
yup, whole 4 fannings
amistre! are you encouraging students on using calculators instead of thinking about it?!
at 101 fans you get to be a "hero"....its a shame really, all that work just to become a sandwich....
different times, different accounts, but same me
:) I don't really care much about the fanning process
the mr proffesor is more of an "exercise" in math than it is a calculator :)
lol, anyway did you understand it deidre? ^_^
@sstarica: I'm not sure if your method works, it ends up giving you -1/3 * ∫1/cos^5(x) dx. :/
2x6=? 12 (green light)
for reals? let me try
Whoops, not quite..
no lol , it works!
Oh, sorry. Thought you typed something else ;P
wait, you're right it doesn't work ^^" sorry for the mess again diedre, ignore my answer. Thank you Quantum ^_^
deidre is away, geting some hotdogs for me and me
Now let me check if my answer works...xD
so dont worry, you have some time to clear the mess before he comes back
\[du = -3x^2sinx^3dx\] which is wrong. you can't substitute it there, my dearest apologies ^^"
Ah, let me expand my answer to make it clearer: ∫tan(x)sec^2(x) dx - ∫tan(x) dx. In the first integral, let u=tan(x), and in the second it integrates cleanly. :P
why did you put tanxsec^2x? where did you get it from
x^3 acts as an angle here
and not the power of tan :)
ok, guys, I am about to go to sleep, just going to workout abit and maybe eat something and i am off.
same, I'm tired
oh, nice, so we are going to beds together again
anyway, solve the question and I'm off to bed, sorry ^_^
I'm going to bed ALONE >_>
I sayed BEDS with an S, not BED :D LOL, I knew it you have interesting thoughts in your head :)
I got it from the relation tan^2(x) = sec^2(x) - 1. ∫tan^3(x)dx = ∫tan^2(x)*tan(x) dx = ∫(sec^2(x)-1)*tan(x) dx = ∫tan(x)sec^2(x) - tan(x) dx = ∫tan(x)sec^2(x) dx - ∫tan(x) dx. :P
nope :)
I never think of such things angoo =P
yes but quantum the question is :\[\int\limits_{}^{}tanx^3\] and not : \[\int\limits_{}^{}\tan^3x\]
hmm... well, I don't too, becouse things like those should be practice once married
I agree :)
quantum you copied the question wrong lol
good, smart girl, not the "new era" type
nah, I'm old fashioned ^_^ more classy
wonderful, smart, classy, what else could one want....
want what? ._.
Erm...alright, then we'll see when deidre clears it up. :P
like in, what else would I look for in a friend
lol , I agree Quantum
aww, angoo, you're soo sweet ^_^
im sticking with my safety net....(S) x^2 dx..... :)
not sweet, just relaxed and not trying to be someone I am not
lol amistre! and yes you are sweet andy ^_^
well, thanks, going to the dream world now, I think I will dream about beautiful land with happy little rabbits and dears and bears living together, and I will be ther too, we will play and have fun....
lala land, lol, I'm off to bed too, good night ^_^
and you are welcome :)
night night :)
sleep tight ~
:) I was about to say "don't let the bugs bite" but it is getting old, so..
lol, bye
bye
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